CS3530 Assignment 1



Kennesaw State University    
Department of Computer Science
CS3530 Operating Systems Section 01
Assignment #1 Evaluating System Performance

Dalibor Labudovic

06/5/2013









Initial Problem Statement:
1.)    Copy the "batch.cpp" source file from the system directory /home/jgarrido/psim3 on CS3 compile and link using the "psim3c" script file. The 'psim3c' script is a command file that uses the GNU C++ compiler on the CS3 server. Follow the instructions in the documents provided in the course Web page.

2.)    Run (execute) the program at least three times.

3.)    Write a report describing the characteristics of the operating system modeled. Use the guidelines for structuring the report.

4.)    Change by a small amount a workload parameter (inter-arrival interval, memory requirements) in the program by executing it again.

5.)    Include at the end of the report your answers to the following questions.
a.)    What aspect of an operating system is the model representing?
b.)    What performance measures does the model compute?
c.)    What is noticeable in the dynamic behavior of the system?
d.)    After changing some of the parameters in the model (the workload) and recompiling. What changes in the results do you notice?
e.)    What other performance measures can this model compute?
f.)     If the model needs to change the representation of a CPU twice as fast as the previous one, how can you implement this modification?


Summary and purpose of the assignment activity:
The summary and purpose of the assignment activity is to evaluate the performance of the computing machine. A testing program has the ability to analyze the performance of a computing power and to alter the parameters and further analyze the outcome. In this assignment, the purpose is to set job inter-interval arrival time and adjust the memory to evaluate the outcome.
Detail description of the solution and used in the project:
The solution for this project is to review the best possible combination of parameter setting to gain a faster processing time. With the current setting under the simuModidfied output, the best combination is to set the inter-interval time set lower, default is 10 and under my setting it was at 5. The other setting is the memory requirements, the default is set at 40 while my settings are at 1000. This combination set the faster service factor .019 time interval.
Table of results:
1.)   First simulation:
a.      Service factor: 0.220307
b.     Processor utilization: 0.352694
c.      Total jobs arrived: 92
d.     Total jobs rejected: 0
e.      Throughput (jobs completed): 92
f.      Proportion Rejected: 0
g.     Average job wait period: 40.7031
h.     Average memory used: 3.97906
2.)    Second simulation:
a.      Service factor: 0.0819463
b.     Processor utilization: 0.437355
c.      Total jobs arrived: 84
d.     Total jobs rejected: 0
e.      Throughput (jobs completed): 84
f.      Proportion Rejected: 0
g.     Average job wait period: 174.991
h.     Average memory used: 4.80327

3.)   Third simulation:
a.      Service factor: 0.108132
b.     Processor utilization: 0.400463
c.      Total jobs arrived: 97
d.     Total jobs rejected: 0
e.      Throughput (jobs completed): 97
f.      Proportion Rejected: 0
g.     Average job wait period: 102.154
h.     Average memory used: 4.2638
4.)   Modified simulation:
a.      Service factor: 0.0195652
b.     Processor utilization: 0.714141
c.      Total jobs arrived: 186
d.     Total jobs rejected: 0
e.      Throughput (jobs completed): 186
f.      Proportion Rejected: 0
g.     Average job wait period: 577.202
h.     Average memory used: 7.71982

Discussion of how the system modeled can be improved and extended to include other service:
The system could be improved with further system adjustments of the memory parameters and inter-intervals to gain a better balance between the service factor and the average job wait period. With the balance be will be at an optimized processing speed and reduced wait time. The optimization however could be fun through an optimization model to gain results faster than trail and error.

Comments and Conclusion:
Utilizing the C program to further gain knowledge about the process of a operating system is valuable and to analyze the process speed. I think, we need to test and continue to research how to improve and better the collaborations between central processing unit and random access memory. This type of research will further improve the speed of the system as a whole.
List of References:
Garrido C., Jose. Using CS3.  CS 3530 .Web.Science.kennesaw.edu/~jgarrido/os/using_CS3.doc 05/03/2013
QUESTIONS:
a.)    What aspect of an operating system is the model representing?
The model represents the processing aspect of an operating system. This includes the job queue waiting time, processed time and memory allocated.

b.)    What performance measures does the model compute?
The model computes Service factor, Processor Utilization and Average wait time, average memory used performance measures.

c.)    What is noticeable in the dynamic behavior of the system?
The dynamic behavior of the system is the job are never in this instance rejected but are sent back of the queue if they are taking too long to process.
d.)    After changing some of the parameters in the model (the workload) and recompiling. What changes in the results do you notice?  
With the increase of memory to the batch file, from 40 memory units to 1000 memory units, the results yield  service factor .17 , processor utilization .36 and wait period of 58 time units. This change has brought more efficiently to the system because processor is utilized  about 50% less, wait time has dropped dramatically from 577 time units to 58 time units, a 10 times less wait time.

e.)    What other performance measures can this model compute?
This model can compute total jobs arrived and throughput completed jobs, with the necessary information of if jobs were rejected.

f.)     If the model needs to change the representation of a CPU twice as fast as the previous one, how can you implement this modification?
To make the CPU twice as fast as previous one, we need to change the workload, increase queue array and increase memory required, and finally increase inter-interval time units.


Script:
Script started on Sun 02 Jun 2013 12:03:01 PM EDT
]0;dlabudov@cs3:~/myos[dlabudov@cs3 myos]$ nano batch.cpp[3Ppsim3cbatch.cpp[1Psiml.txtls[Kcd myos./batch | tee simul.txt[Kmv a.out batch./psim3c batch.cppcp /home/jgarrido/psim3/psim3c .
[C[C[C[C[C[C[C[C[C[C[C[C[C[C[C[C[C[C[C[C[C[14P./psim3c batch.cpp[4Pmv a.out batch[7P./batch | tee simul.txt
[C[C[C[C[C[C[C[C[C[C[C[C[C[C[C[C[C[C[C[C[Ccd myos[Kls[Kcd myos./batch | tee simul.txt[Kmv a.out batch[K[K[K[K[K[K[K[K[K[K[K[K[K[K./psim3c batt[Kch.cpp
[H[2J[H[2J-------------------------------------------------------------------------------
------ Psim3 C++ (POSIX threads) package for object oriented simulation -------
------------------ (C) J. M. Garrido, 2004-2012 -----------
-------------------------------------------------------------------------------
a.out created.
                 
]0;dlabudov@cs3:~/myos[dlabudov@cs3 myos]$ mv a.out batch
]0;dlabudov@cs3:~/myos[dlabudov@cs3 myos]$ ./batch  tee simu1.txt
Psim3 project: Simple Batch System
Simulation date: Sun Jun  2 12:06:15 2013
Simulation parameters
Simulation interval: (3000)
Close arrival time: (1000)
Workload Parameters
Mean inter-arrival: (10.55)
Mean CPU service demand: (12.65)
Lower bound mean memory demand: (8)
Upper bound mean mem demand: (14)


 Systems parameters
Queue capacity: (200)
System memory: (40)
Processor object created
environment created with 10.55 12.65


Service factor: 0.0658138
Processor utilization: 0.423735
Total jobs arrived: 98
Total jobs rejected: 0
Throughput (jobs completed): 98
Proportion Rejected: 0
Average job wait period: 184.122
Average memory used: 4.61086
--------------------------------------------------
 End of simulation Simple Batch System Sun Jun  2 12:06:15 2013




]0;dlabudov@cs3:~/myos[dlabudov@cs3 myos]$
]0;dlabudov@cs3:~/myos[dlabudov@cs3 myos]$ .batch | tee simu2.txt
bash: .batch: command not found
]0;dlabudov@cs3:~/myos[dlabudov@cs3 myos]$ ./batch | tee simu2.txt
Psim3 project: Simple Batch System
Simulation date: Sun Jun  2 12:07:36 2013






 Simulation parameters
Simulation interval: (3000)
Close arrival time: (1000)


 Workload Parameters
Mean inter-arrival: (10.55)
Mean CPU service demand: (12.65)
Lower bound mean memory demand: (8)
Upper bound mean mem demand: (14)


 Systems parameters
Queue capacity: (200)
System memory: (40)
Processor object created
environment created with 10.55 12.65
CPU goes idle at 0
environment generating  at 21.0393



Service factor: 0.0819463
Processor utilization: 0.437355
Total jobs arrived: 84
Total jobs rejected: 0
Throughput (jobs completed): 84
Proportion Rejected: 0
Average job wait period: 174.991
Average memory used: 4.80327
--------------------------------------------------
 End of simulation Simple Batch System Sun Jun  2 12:07:36 2013




]0;dlabudov@cs3:~/myos[dlabudov@cs3 myos]$ ./batch | tee simu3.txt
Psim3 project: Simple Batch System
Simulation date: Sun Jun  2 12:08:22 2013


 Simulation parameters
Simulation interval: (3000)
Close arrival time: (1000)


 Workload Parameters
Mean inter-arrival: (10.55)
Mean CPU service demand: (12.65)
Lower bound mean memory demand: (8)
Upper bound mean mem demand: (14)


 Systems parameters
Queue capacity: (200)
System memory: (40)


Service factor: 0.108132
Processor utilization: 0.400463
Total jobs arrived: 97
Total jobs rejected: 0
Throughput (jobs completed): 97
Proportion Rejected: 0
Average job wait period: 102.154
Average memory used: 4.2638
--------------------------------------------------
 End of simulation Simple Batch System Sun Jun  2 12:08:22 2013




]0;dlabudov@cs3:~/myos[dlabudov@cs3 myos]$ .batch | tee simuModfied.txt
bash: .batch: command not found
]0;dlabudov@cs3:~/myos[dlabudov@cs3 myos]$ ./batch | tee simuModified.txt
Psim3 project: Simple Batch System
Simulation date: Sun Jun  2 12:09:53 2013



 Simulation parameters
Simulation interval: (3000)
Close arrival time: (1000)

 Workload Parameters
Mean inter-arrival: (10.55)
 Mean CPU service demand: (12.65)
Lower bound mean memory demand: (8)
Upper bound mean mem demand: (14)

 Systems parameters
Queue capacity: (200)
 System memory: (40)
 Processor object created environment created with 5   12.65
Service factor: 0.0195652
Processor utilization: 0.714141
Total jobs arrived: 186
Total jobs rejected: 0
Throughput (jobs completed): 186
Proportion Rejected: 0
Average job wait period: 577.202
Average memory used: 7.71982
--------------------------------------------------
 End of simulation Simple Batch System Sun Jun  2 12:09:53 2013




]0;dlabudov@cs3:~/myos[dlabudov@cs3 myos]$ exit
exit

Script done on Sun 02 Jun 2013 12:11:34 PM EDT

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